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【标 题】:一个表单数据检查思路....
【关键字】:
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【来 源】:http://blog.csdn.net/km3945/archive/2007/01/22/1490207.aspx
一个表单数据检查思路....
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<title>无标题文档</title>
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<style type="text/css"><!--
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a, a:link{text-decoration: none; color:#000000; font-size:9pt;} a:visited{text-decoration: none; color:#000000;} a:hover{text-decoration: underline; color:red;}
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body, td, p, li, div, select{font-size:9pt; font-family:"宋体";}
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--></style>
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</head>
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<body>
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<?php
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/*
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检测表单数据,
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一至以来都想做个方便一点的表单数据检查程序.但看来看去没有什么好方法,
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这是今天想到的.利用表单元素的NAME属性.
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我们在定义表单元素时,把NAME的属性定义成带数据类型的格式如:
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<input type="text" name="test_s_n" />
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该IPNUT是s[String],n[noNull],test就是表单的表意词.
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意思就是TEST是字符串,不能为空.
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有些东西想的不是太清楚.只是一种思路.
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下面是一个小DEMO
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*/
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if($_SERVER['REQUEST_METHOD'] == 'POST')
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{
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checkPost($_POST);
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echo '<pre>'.print_r($_POST, true).'</pre>';
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}
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function checkPost($data)
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{
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foreach($data as $key=>$val)
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{
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list($name, $type) = explode('_', $key, 2);
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if(!is_null($type))
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{
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if(!ck($val, $type)) die($key .'类型不匹配!');
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}
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}
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}
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function ck($value, $type)
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{
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$a =array();
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$types = explode('_', $type);
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foreach($types as $t)
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{
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if('s' == $t)
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{
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$a[$t] = is_string($value);
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}
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if('i' == $t)
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{
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$a[$t] = is_numeric($value);
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}
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if('n' == $t)
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{
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$a[$t] = !empty($value);
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}
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}
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return in_array(true, $a);
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}
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?>
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<form name="form1" method="post" action="">
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<input type="text" name="test_s_n" />
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<input type="submit" value="Submit" name="b1" />
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<input type="reset" value="Reset" name="b3" />
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</form>
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</body>
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</html>