为DataGrid动态创建模板列，首先要实现ITemplate接口：
public class MyDataGridTemplate : System.Web.UI.ITemplate
{
ListItemType _litType;
object _objData;
public MyDataGridTemplate(ListItemType litType, object objData)
{
_litType = litType;
_objData = objData;
}
public void InstantiateIn(System.Web.UI.Control container)
{
Literal ltr = new Literal();
TextBox txt = new TextBox();
switch(_litType)
{
case ListItemType.Header:
ltr.Text = "<b>" + _objData.ToString() + "</b>";
container.Controls.Add(ltr);
break;
case ListItemType.Item:
ltr.Text = _objData.ToString();
container.Controls.Add(ltr);
break;
case ListItemType.EditItem:
container.Controls.Add(txt);
break;
case ListItemType.Footer:
ltr.Text = "<i>" + _objData.ToString() + "</i>";
container.Controls.Add(ltr);
break;
}
}
}
现在就可以动态创建模板列了：
TemplateColumn tc;
tc = new TemplateColumn();
tc.HeaderText = "列1";
tc.ItemTemplate = new MyDataGridTemplate(ListItemType.Item, "列1");
dg.Columns.Add(tc);
tc = new TemplateColumn();
tc.HeaderText = "列2";
tc.ItemTemplate = new MyDataGridTemplate(ListItemType.Item, "列2");
dg.Columns.Add(tc);
以上代码的效果与下列代码相同：
<asp:TemplateColumn HeaderText="列1">
<ItemTemplate>
<asp:Literal Runat="server" Text="列1"></asp:Literal>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="列2">
<ItemTemplate>
<asp:Literal Runat="server" Text="列2"></asp:Literal>
</ItemTemplate>
</asp:TemplateColumn>
franz
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